60. Permutation Sequence

problem description

The set [1,2,3,...,n] contains a total of n! unique permutations.

By listing and labeling all of the permutations in order, we get the following sequence for n = 3:

  1. "123"

  2. "132"

  3. "213"

  4. "231"

  5. "312"

  6. "321"

Given n and k, return the kth permutation sequence.

Note:

  • Given n will be between 1 and 9 inclusive.

  • Given k will be between 1 and n! inclusive.

Example 1:

Input: n = 3, k = 3
Output: "213"

Example 2:

Input: n = 4, k = 9
Output: "2314"

algorithm thought

n个数排列有n!种情况,如果数字是1-n,那么1开头的排列会有(n-1)!个。同理可以退出,如果需要找第k个排列,第一个字符我们是可以确定的。然后利用递归的思路,一直将数字推出。

code

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